Write a Java Program to check User Enter Number is Even Or Odd?

//Qus.#2:- check User Enter Number is Even Or Odd?

Solution:-

 import java.util.Scanner;  
 public class Even_Or_Odd {  
      public static void main(String[] args) {  
           Scanner sc= new Scanner(System.in);  
           System.out.println("Enter the number");  
           int n =sc.nextInt();  
           if(n%2==0)  
           {  
                System.out.println(n+" User Enter Number Is Even");  
           }  
           else  
           {  
                System.out.println(n+" User Enter Number Is Odd");  
           }  
      }  
 }  

🤖Explanation: let's suppose User Entered Number is (n=22)
👉 n=n%2  (Always Gives Reminder)
👉 n=22%2
👉 reminder = 0

Let's Check the condition (n%2==0)
👉 22%2=0
👉 0=0 ( Condition Satisfied that's why this number is Even)

🤙Note:- If we get 1 Reminder then the number is Odd 
           If we get 0 Reminder then the number is Even

🤦‍♂️Try Your Self Buddy,  If you Get any Error just Comment Below, Definitely, I will try to Solve Your Problem.

Next Program:- #3.Write a Java Program to Check User Enter Number is Special Two-Digit Number OR not?